Get Unlimited Contributor Access to the all ExamTopics Exams!
Take advantage of PDF Files for 1000+ Exams along with community discussions and pass IT Certification Exams Easily.
What is the worst case acceptance value for attenuation when testing 2000 m (6562 ft) of 50/125 multimode fiber at a wavelength of 1300 nm when the fiber has 2 connector pairs and 3 splices?
Maximum cable attenuation coefficient for 50/125 multimode fiber at a wavelength of 1300 nm is 1.5 dB/km.
So (Maximum channel attenuation – [# connector pairs x 0.75 dB] – [# splices x 0.3 dB])=-1.5dB/km x 2km- 2 x 0.75dB - 3 x 0.3 dB = -5.4dB.
A voting comment increases the vote count for the chosen answer by one.
Upvoting a comment with a selected answer will also increase the vote count towards that answer by one.
So if you see a comment that you already agree with, you can upvote it instead of posting a new comment.
CUB90
7 months, 3 weeks ago[Removed]
1 year, 2 months agoLiONz5
1 year, 7 months ago